Fuselage Group Mass
Consider a 5% weight reduction due to composite usage in nonload-bearing structures (e. g., floorboards). Use Equation 8.15:
L = 15.24 m, Dave = 1.75 m, VD = 380KEAS = 703.76 kmph = 195.5 m/s and Cfus = 0.04, ke = 1.04, kp = 1.09, kuc = 1.06, and kmat = (0.9 + 0.9 x 0.1) = 0.99
Semi-empirical |
Mass |
Graphical |
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Component |
(kg) |
fraction % |
solution – lb (kg) |
|||
1. |
Fuselage group |
930 |
10 |
^2,050 (932) |
||
2. |
Wing group |
864 |
9.2 |
^2,100 (94б) |
||
3. |
H-tail group |
124 |
1.32 |
H-Tail+V-Tail^460 (209) |
||
4. |
V-tail group |
63 |
0.67 |
|||
5. |
Undercarriage group |
380 |
4 |
^900 (409) |
||
6. |
Nacelle + pylon group |
212 |
2.245 |
^410 (18б) |
||
7. |
Miscellaneous Structures group total |
2,591 |
27.56 |
|||
8. |
Power plant group |
1,060 |
11.28 |
|||
9. |
Systems group |
1,045 |
11.12 |
|||
10. |
Furnishing group |
618 |
6.57 |
|||
11. |
Contingencies MEM |
143 |
5,457 |
0.7 |
58.05 |
|
12. |
Crew |
180 |
1.92 |
|||
13. |
Consumables OEM |
^ 119 |
5,800 |
1.73 |
61.7 |
|
13. |
Payload (as positioned) |
1,100 |
11.7 |
|||
14. |
Fuel (as positioned) MTOM |
2,500 |
9,400 |
26.6 |
100 |
|
MRM |
9,450 |
100.53 |
Table 8.5. Bizjet mass (weight) summary |
fuselage
horizonta tail
Then:
MFcivil = cfus X ke X kp X kuc X kdoor X; (MTOM X nult) X (2 X L X Dave X
For civil aircraft, (MTOM x nult)x = 1; therefore:
M-Fcivii = 0.04 X 1.04 X 1.09 X 1.06 x 1 x 1 x (2 x 15.24 x 1.75 x 195.50’5)1’5 = 0.048 x (2 x 15.24 x 1.75 x 195.50’5)1’5 = 0.048 x (53.35 x 13.98)15 = 0.048 x (745.95)15 = 0.048 x 20,373.3 = 978 kg
There is a 5% reduction of mass due to the use of composites:
MFcivil = °.95 MFcivil-all metal ^ 930 kg
This is checked using Torenbeek’s method (Equation 8.13); refer to Chapters 6 and 9 for dimensions:
WFcivil = 0.021 Kf {VdLht/ (W + D)}05 (f s-gross _area )
Kf = 1.08, L = 50 ft, W = 5.68 ft, D = 5.83 ft, Lht = 25 ft, Vd = 380 KEAS,
Sfus „gross – area = 687 ft
Therefore,
WFcivil = 0.021 X 1.08 X 1.07 X {380 x 25/(5.68 + 5.83)}0 5 x (687)12
= 0.0243 x (825.4)0 5 x 2,537.2 = 0.0243 x 28.73 x 2,537.2 = 1,770 lb (805 kg)
The higher value of the two (i. e., 930 kg) is retained, which gives a safer approach initially.